ENGR266 2023 Q A2Past paperOld spec ENGR2662:125 marks30 min

ENGR266 Summer 2023 Q A2[PARTIAL] official answers Left out: Part (b) (excess volume) and part (c) (modified Raoult's law with activity coefficients) go beyond the current formula sheet, which only has ideal Raoult's and Henry's laws. Parts (a) and (d) are on-syllabus.

Answer ALL parts (a) - (d).

Formulas you may need
  • [EXTERNAL] Excess property: VE=V−∑ixiViV^E = V - \sum_i x_i V_i (learn this; not on the current formula sheet)
  • [EXTERNAL] Modified Raoult's law: yiP=xiγiPisaty_i P = x_i\gamma_i P_i^{sat}, so P=∑ixiγiPisatP = \sum_i x_i\gamma_i P_i^{sat} (learn this; the sheet only has ideal Raoult yiP=xiPisaty_i P = x_i P_i^{sat})
  • Antoine equation as given: ln⁡Psat/kPa=A−BT/∘C+C\ln P^{sat}/\mathrm{kPa} = A - \dfrac{B}{T/^\circ\mathrm{C} + C} (given in the question)
  • Equilibrium constant for ideal gases: K=∏i(yiPP∘)νiK = \prod_i\left(\dfrac{y_i P}{P^\circ}\right)^{\nu_i} (on the formula sheet as KP=∏PiνiK_P = \prod P_i^{\nu_i})
  • Extent of reaction: ni=ni0+νiεn_i = n_{i0} + \nu_i\varepsilon, yi=ni/∑niy_i = n_i/\sum n_i (learn this)
  1. (a)
    Sketch a T x y diagram and label the liquid, vapour and liquid-vapour regions as well as the bubble and dew curves
    [5]Third
  2. (b)
    Calculate the excess volume for the propanol(1)/water(2) mixture with a mole fraction of 0.16656 propanol at 25∘C25^\circ\mathrm{C} if the mixture's volume is 27.016 cm3 mol−127.016\ \mathrm{cm^3\,mol^{-1}}. The volume for propanol and water at 25∘C25^\circ\mathrm{C} are 75.168 cm3 mol−175.168\ \mathrm{cm^3\,mol^{-1}} and 18.068 cm3 mol−118.068\ \mathrm{cm^3\,mol^{-1}} respectively.
    [4]Third
  3. (c)
    Calculate the pressure required to hold the chloroform(1)/methanol(2) system in vapour-liquid equilibrium at 36∘C36^\circ\mathrm{C} if the mole fractions of chloroform in the liquid and vapour phase are 0.44 and 0.657 respectively. The activity coefficients are γ1=1.6423\gamma_1 = 1.6423 and γ2=0.9534\gamma_2 = 0.9534 and the saturation pressures can be found using the Antoine equations below: ln⁡PChloroformsat/kPa=13.7324−2548.74T/∘C+218.552\ln P^{sat}_{Chloroform}/\mathrm{kPa} = 13.7324 - \dfrac{2548.74}{T/^\circ\mathrm{C} + 218.552} ln⁡PMethanolsat/kPa=16.5785−3638.27T/∘C+239.500\ln P^{sat}_{Methanol}/\mathrm{kPa} = 16.5785 - \dfrac{3638.27}{T/^\circ\mathrm{C} + 239.500}
    [4]2:2
  4. (d)
    The cracking of pure n-butane via the reaction below is performed at 750 K, where the equilibrium constant, KK, for the reaction is 6.0. C4H10→C2H4+C2H6C_4H_{10} \rightarrow C_2H_4 + C_2H_6 Calculate the mole fractions for all species if the reaction starts from 1 mole of C4H10 and is carried out in the gas phase where the pressure is 2 bar and standard pressure is 1 bar. You can assume all species are ideal gasses.
    [12]