ENGR201 2021 Q2Past paperOld spec ENGR2012:125 marks30 min

ENGR201 Engineering Analysis 2021 (Michaelmas) Q2[VALID] official answers

Consider the initial value problem of a dynamic system subjected to the exponential input e2te^{2t}:

d2ydt2−2dydt+y=e2t\frac{d^2y}{dt^2} - 2\frac{dy}{dt} + y = e^{2t}

with initial conditions y(0)=dy(0)dt=0y(0) = \dfrac{dy(0)}{dt} = 0.

Formulas you may need
  • L[y′]=sY−y(0)\mathcal{L}[y'] = sY - y(0), L[y′′]=s2Y−sy(0)−y′(0)\mathcal{L}[y''] = s^2Y - sy(0) - y'(0) (learn this; printed in the ENGR201 Laplace table)
  • eat↔1s−ae^{at} \leftrightarrow \dfrac{1}{s - a}, t eat↔1(s−a)2t\,e^{at} \leftrightarrow \dfrac{1}{(s - a)^2} (learn this; printed in the ENGR201 Laplace table)
  • Impulse δ(t−a)↔e−as\delta(t - a) \leftrightarrow e^{-as}; delay Ha(t)g(t−a)↔e−asG(s)H_a(t)g(t - a) \leftrightarrow e^{-as}G(s) (learn this; printed in the ENGR201 Laplace table)
  • Repeated-root partial fractions As−2+Bs−1+C(s−1)2\dfrac{A}{s - 2} + \dfrac{B}{s - 1} + \dfrac{C}{(s - 1)^2} (learn this)
  1. (a)
    Use the Laplace transform to solve the initial value problem (show your workings).
    [18]2:2
  2. (b)
    If the system is subjected to an additional impulse input δ(t−2)\delta(t - 2), use the Laplace transform again to solve the problem (show your workings).
    [5]
  3. (c)
    Will the solution from (b) be discontinuous at t=2t = 2? Explain your answer.
    [2]