ENGR217 2017 Q B3Past paperOld spec ENGR2172:225 marks30 min

ENGR217 Summer 2017 Q B3[VALID]

Answer ALL parts (a) - (c)

Formulas you may need
  • Ideal gas: pV=mRgTpV = mR_gT, so m˙=pV˙RgT\dot m = \dfrac{p\dot V}{R_g T}, with Rg=0.287 kJ kg−1 K−1R_g = 0.287\ \mathrm{kJ\,kg^{-1}\,K^{-1}} (on the formula sheet)
  • SFEE: Q˙−W˙=m˙[(h+C22+gZ)out−(h+C22+gZ)in]\dot Q - \dot W = \dot m\left[\left(h + \tfrac{C^2}{2} + gZ\right)_{out} - \left(h + \tfrac{C^2}{2} + gZ\right)_{in}\right] (on the formula sheet)
  • Ideal gas enthalpy change: dh=cp dTdh = c_p\,dT, cp=γRgγ−1c_p = \dfrac{\gamma R_g}{\gamma-1} (on the formula sheet)
  • Heat picked up by the cooling water: Q˙=m˙c ΔT\dot Q = \dot m c\,\Delta T (on the formula sheet as dQ=mcpdTdQ = m c_p dT)
  1. (a)
    An air compressor delivers a volume 0.90 m30.90\ \mathrm{m^3} per minute of air at 6.5 bar pressure (absolute) and 20∘C20^\circ\mathrm{C}. Calculate the mass flow rate of air through the compressor, in kg/s.
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  2. (b)
    The compressor operates steadily, with air entering the compressor at 1.0 bar and temperature 18∘C18^\circ\mathrm{C}, and exiting at 6.5 bar and 140∘C140^\circ\mathrm{C}. The velocity of the air at inlet to the compressor is 90 m/s, and the velocity at the outlet is 35 m/s. If no heat is lost, estimate the power required to drive the compressor.
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  3. (c)
    To reduce the driving power required and to lower the temperature of the delivered air, the compressor is cooled by a water jacket through which water is pumped at a rate 0.04 kg/s. The water enters at 25∘C25^\circ\mathrm{C} and it leaves at 48∘C48^\circ\mathrm{C}. The compressor continues to pass air at the same mass flow rate and the entry temperature is unchanged, but the temperature of the air at exit is now 66∘C66^\circ\mathrm{C}. Estimate the power now consumed by the compressor, taking the specific heat of water as 4.19 kJ kg−1 K−14.19\ \mathrm{kJ\,kg^{-1}\,K^{-1}}, and assuming the same air velocities as before.
    [7]