ENGR217 2025 Q A1Past paperOld spec ENGR2172:125 marks30 min

ENGR217 Summer 2025 Q A1[VALID] official answers

Answer all parts (a) - (c).

Formulas you may need
  • Bernoulli with head loss: v122g+z1+p1ρg=v222g+z2+p2ρg+hL\dfrac{v_1^2}{2g} + z_1 + \dfrac{p_1}{\rho g} = \dfrac{v_2^2}{2g} + z_2 + \dfrac{p_2}{\rho g} + h_L (on the formula sheet)
  • Darcy-Weisbach: Δp=f LD ρv22\Delta p = f\,\dfrac{L}{D}\,\dfrac{\rho v^2}{2}, hL=f LD v22gh_L = f\,\dfrac{L}{D}\,\dfrac{v^2}{2g} (ff = Darcy factor) (on the formula sheet)
  • Reynolds number: Re=ρvDμ=vDνRe = \dfrac{\rho v D}{\mu} = \dfrac{vD}{\nu}; laminar below about 2300, turbulent above 4000 (on the formula sheet)
  • Moody chart / Colebrook: 1f=−2log⁡10(k/D3.7+2.51Ref)\dfrac{1}{\sqrt f} = -2\log_{10}\left(\dfrac{k/D}{3.7} + \dfrac{2.51}{Re\sqrt f}\right) (learn this; the Moody chart is supplied with the paper)
  • Hagen-Poiseuille: Δp=8μLQπR4\Delta p = \dfrac{8\mu L Q}{\pi R^4}, i.e. Q=π Δp R48μLQ = \dfrac{\pi\,\Delta p\,R^4}{8\mu L} (on the formula sheet)
  • Continuity: Q=vAQ = vA (on the formula sheet)
  1. (a)
    Water at 12∘C12^\circ\mathrm{C} is supplied to a 40 mm diameter steel pipe at 9 bar gauge pressure. The pipe is 125 m long, the roughness is k=0.02k = 0.02 mm, and at the end of the pipe the water is discharged to atmosphere. Estimate the volume flow rate of the water. (Kinematic viscosity for the water is ν=1.22×10−6 m2/s\nu = 1.22 \times 10^{-6}\ \mathrm{m^2/s}).
    [15]
  2. (b)
    Diesel fuel flows along a pipe 12 m long, whose bore (internal diameter) is 8 mm. The density and viscosity of the fuel are 850 kg/m3850\ \mathrm{kg/m^3} and 1.8×10−3 N s/m21.8 \times 10^{-3}\ \mathrm{N\,s/m^2} respectively. If the pressure drop over the length of the pipe 1.5 kN/m21.5\ \mathrm{kN/m^2}, estimate the volume flow rate of fuel along the pipe. (Hint: use Poiseuille's equation.)
    [6]Third
  3. (c)
    Hot water at 50∘C50^\circ\mathrm{C} is flowing along a pipe 800 mm diameter at a mean speed of 2.3 m/s. At this temperature the kinematic viscosity of the water is ν=5.55×10−7 m2/s\nu = 5.55 \times 10^{-7}\ \mathrm{m^2/s}. Will the flow be laminar or turbulent?
    [4]Third