ENGR263 Process of Mass and Heat Transfers 2017 Section A Q A2[VALID] official answers
Answer ALL parts (a) - (b).
Formulas you may need
- Diffusion through a stagnant gas: , (on the formula sheet)
- Multicomponent stagnant mixture: , (on the formula sheet; also given in the question)
- Sherwood number (on the formula sheet; also given in the question)
- Radial diffusion from a sphere: (on the formula sheet)
- (a(i))[3]ThirdWhat is the difference between the diffusivity or diffusion coefficient () and the mass transfer coefficient?
- (a(ii))[5]Prove that for equimolecular counter diffusion from a sphere to a surrounding stationary infinite medium, the Sherwood number based on the diameter of the sphere is equal to 2. (Data: the Sherwood number is defined as , where is the mass transfer coefficient based on concentration () and is the diffusivity of component A in the medium B ().)
- (b(i))[9]2:2Ammonia gas is diffusing at a constant rate through a layer of 1 mm thickness of stagnant air. Conditions are fixed so that the gas contains 50 % by volume of ammonia at one boundary of the stagnant layer. The ammonia diffusing to the other boundary is quickly absorbed and the concentration is then negligible. The temperature is 295 K and the pressure is atmospheric, and under these conditions the diffusivity of ammonia in air is . Calculate the flux of mass transfer of ammonia ().
- (b(ii))[8]2:2Assuming that the non-diffusing gas (air) is replaced by a mixture of methane (B) and hydrogen (C) in volume ratio 2:1, re-calculate the flux of mass transfer of ammonia, if the diffusivity of ammonia in methane and the diffusivity of ammonia in hydrogen are and , respectively. (Data: the diffusivity of a component in a multicomponent mixture follows the Stefan-Maxwell model , .)