ENGR263 2021 Q A1Past paperOld spec ENGR2632:216 marks19 min

ENGR263 Process of Mass Transfer Summer 2021 (open book) Q A1[VALID] official answers

Answer BOTH parts (a) and (b).

Formulas you may need
  • Wilke-Chang: DAB=7.4×10−8(ΦBMB)1/2TμBVA0.6D_{AB} = \dfrac{7.4 \times 10^{-8}(\Phi_BM_B)^{1/2}T}{\mu_BV_A^{0.6}} with DD in cm2/s\mathrm{cm^2/s}, μB\mu_B in cP, VAV_A in cm3/mol\mathrm{cm^3/mol}, TT in K, MBM_B and ΦB\Phi_B of the solvent (on the formula sheet)
  • Equimolar counter-diffusion through a film: NA=−NB=cDABδ(yA1−yA2)=DABRTδ(pA1−pA2)N_A = -N_B = \dfrac{cD_{AB}}{\delta}(y_{A1} - y_{A2}) = \dfrac{D_{AB}}{RT\delta}(p_{A1} - p_{A2}), c=P/(RT)c = P/(RT) (on the formula sheet)
  1. (a)
    Compare estimates of the diffusion coefficient of an ethanol-water mixture at 10∘C10^\circ\mathrm{C} (283 K), under conditions that (1) ethanol is the solute and water is the solvent and (2) water is the solute and ethanol is the solvent. Ethanol has the molecular formula C2_2H5_5OH and a molecular weight of 46 g/gmole, and water (H2_2O) has a molecular weight of 18 g/gmole. At 10∘C10^\circ\mathrm{C}, the liquid viscosity of water is 1.306×10−31.306 \times 10^{-3} Pa s (1.306 cP), and the liquid viscosity of ethanol is 1.394×10−31.394 \times 10^{-3} Pa s (1.394 cP). The molecular volume of water is 18.9 cm3/gmole18.9\ \mathrm{cm^3/gmole} and the molar volume of ethanol (EtOH) 59.2 cm3/gmole59.2\ \mathrm{cm^3/gmole}. The association parameter of the solvent Φwater=2.6\Phi_{water} = 2.6 and ΦEtOH=1.5\Phi_{EtOH} = 1.5.
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  2. (b)
    In a rectification column, toluene is diffusing from gas to liquid and benzene from liquid to gas at temperature of 30∘C30^\circ\mathrm{C} and pressure 101.3 kN/m2101.3\ \mathrm{kN/m^2} under conditions of equal molar counter diffusion. At one point in the column, the molal concentrations of toluene on the two sides of a gas film 0.5 mm thick are 70% and 20%, respectively. Assuming the diffusivity of benzene-toluene vapour under the operating conditions to be 0.38×10−5 m2/s0.38 \times 10^{-5}\ \mathrm{m^2/s}, estimate the rate of diffusion of toluene and benzene in kg/hr across an area of 0.01 m20.01\ \mathrm{m^2}. The molecular weights of toluene and benzene are 92 and 78 g/mol, respectively. The ideal gas constant is equal to 8.314 m3 Pa K−1 mol−18.314\ \mathrm{m^3\,Pa\,K^{-1}\,mol^{-1}}.
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