ENGR273 2026 Q4Past paperCurrent specFirst25 marks30 min

ENGR273 Summer 2026 Q4[VALID] official answers

A uniform slender rod AB of mass mm has its ends constrained to move in two smooth guides (Figure Q4-1).

  • End A slides on the horizontal guide y=0y = 0.
  • End B slides on a straight guide inclined at angle β\beta to the +x+x axis (guide line passes through the origin), i.e. y=(tan⁡β) xy = (\tan\beta)\,x, 0<β<90∘0 < \beta < 90^\circ.

At the instant shown:

  • A=(xA,0)A = (x_A, 0) with known speed and acceleration to the right: vA=vA i\mathbf{v}_A = v_A\,\mathbf{i}, aA=aA i\mathbf{a}_A = a_A\,\mathbf{i}.
  • B=(xB,xBtan⁡β)B = (x_B, x_B\tan\beta) with known acceleration magnitude aBa_B along the inclined guide as shown in figure Q4-1 (direction +t+\mathbf{t}, where t\mathbf{t} is the unit tangent of the guide).

A driving actuator applies an unknown force P\mathbf{P} at A along +x+x (through the slider at A). Neglect gravity. Positive angular sense is counterclockwise +k+\mathbf{k}. L=ABL = AB.

Figure Q4-1: rod AB with A on the horizontal guide and B on the guide y = x tan(beta).
Figure Q4-1: rod AB with A on the horizontal guide and B on the guide y = x tan(beta).
Formulas you may need
  • Instantaneous centre of zero velocity: intersection of the perpendiculars to two known velocity directions; v=ω r/ICv = \omega\, r_{/IC} (learn this)
  • Relative velocity vB=vA+ω×rB/A\mathbf{v}_B = \mathbf{v}_A + \boldsymbol\omega\times\mathbf{r}_{B/A} (learn this)
  • Relative acceleration aB=aA+α×rB/A−ω2rB/A\mathbf{a}_B = \mathbf{a}_A + \boldsymbol\alpha\times\mathbf{r}_{B/A} - \omega^2\mathbf{r}_{B/A} (learn this)
  • Equations of motion ∑F=maG\sum\mathbf{F} = m\mathbf{a}_G, ∑MG=IGα\sum M_G = I_G\alpha, or about any point P: ∑MP=IGα+(rG/P×maG)⋅k\sum M_P = I_G\alpha + (\mathbf{r}_{G/P}\times m\mathbf{a}_G)\cdot\mathbf{k} (learn this)
  • Slender rod IG=112mL2I_G = \dfrac{1}{12} m L^2 (given in the question)
  1. (a)
    Draw the free-body diagram and kinetic diagram of rod AB. Indicate guide reactions at A and B, the actuator force P\mathbf{P}, mass centre G, and inertia terms maGm\mathbf{a}_G and IGI_G (with IG=112mL2I_G = \frac{1}{12} m L^2).
    [8]2:2
  2. (b)
    Determine the instantaneous centre of zero velocity (IC) of rod AB and locate it relative to points A and B. Hence determine the instantaneous angular velocity ωAB\boldsymbol{\omega}_{AB} and the instantaneous velocity of the mass centre G.
    [10]2:1
  3. (c)
    Using planar rigid-body acceleration relations, determine the instantaneous angular acceleration αAB\boldsymbol{\alpha}_{AB} and the acceleration of the mass centre aG\mathbf{a}_G. Hence determine the actuator force P\mathbf{P} and the guide reactions at A and B required at this instant (in terms of the given variables).
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