ENGR216 2025 Q B1Past paperOld spec ENGR2162:125 marks30 min

ENGR216 Summer 2025 Q B1[VALID] official answers

A uniform rod OA with a mass (mm) and length (LL) is centrally affixed to a uniform block of mass (mm). 'O' is the centre of rotation for the rod OA, which is also the centroid of the block, as shown in Figure B1. The block is positioned to move freely along a smooth horizontal surface. Initially, the system is at rest, and the rod OA is oriented horizontally with an initial counterclockwise angular velocity ωOA\omega_{OA}.

Figure B1: block of mass m on a smooth floor with rod OA (mass m, length L) pinned at the block centroid O.
Figure B1: block of mass m on a smooth floor with rod OA (mass m, length L) pinned at the block centroid O.
Formulas you may need
  • Relative acceleration (rigid body): aG=aO+α×rG/O−ω2rG/O\mathbf{a}_G = \mathbf{a}_O + \boldsymbol\alpha\times\mathbf{r}_{G/O} - \omega^2\mathbf{r}_{G/O} (learn this)
  • Equations of motion: ∑F=maG\sum\mathbf{F} = m\mathbf{a}_G, ∑MG=IGα\sum M_G = I_G\alpha; for a translating body ∑F=ma\sum\mathbf{F} = m\mathbf{a} (learn this)
  • Slender rod about its centre: IG=112mL2I_G = \dfrac{1}{12} m L^2 (learn this)
  • Moments about another point P (check): ∑MP=IGα+(rG/P×maG)z\sum M_P = I_G\alpha + (\mathbf{r}_{G/P}\times m\mathbf{a}_G)_z (learn this)
  • Newton's third law at a pin: equal and opposite pin forces on the two bodies (learn this)
  • Friction: static F≤μsNF \le \mu_s N, kinetic F=μkNF = \mu_k N, opposing the (impending) relative sliding (learn this)
  1. (a)
    Draw the free-body and kinetic diagrams of the rod OA and the block. State appropriate coordinate systems.
    [10]
  2. (b)
    Determine the acceleration of point O on the initial instant.
    [5]
  3. (c)
    Determine the angular acceleration of the rod OA at the instant of (b).
    [5]2:2
  4. (d)
    If there is friction between the block and the horizontal surface, will the acceleration of point O increase or decrease? Give your reasoning.
    [5]