Dynamics L6 Worked example 1TutorialOld spec ENGR2162:210 min

ENGR216 Dynamics L6 worked example 1 (slides 12-14) official answers

A 10 kg block on a smooth horizontal surface (μk=0\mu_k = 0) is pushed by a constant force F=500F = 500 N whose line of action slopes downwards towards the block with a 3-4-5 slope (4 horizontal, towards the spring; 3 vertical, downwards). A spring of stiffness k=500k = 500 N/m is mounted between the block and a wall ahead of it. When s=0s = 0 the block is at rest and the spring is uncompressed; ss is the block's displacement towards the wall. Take g=9.81g = 9.81 m/s2^2.

10 kg block pushed by F = 500 N along a 3-4-5 slope (down and to the right) towards a spring k = 500 N/m attached to a wall; s is the block displacement.
10 kg block pushed by F = 500 N along a 3-4-5 slope (down and to the right) towards a spring k = 500 N/m attached to a wall; s is the block displacement.
Formulas you may need
  • Newton's second law: ∑Fx=max\sum F_x = m a_x, ∑Fy=may\sum F_y = m a_y (learn this)
  • Linear spring: Fs=ksF_s = k s (learn this)
  • a ds=v dva\,ds = v\,dv when a=a(s)a = a(s) (learn this)
  1. (a)
    Draw the free-body and kinetic diagrams of the block and find the normal reaction and a(s)a(s).
  2. (b)
    Find the velocity of the block when s=0.5s = 0.5 m.