Old spec 3.5 example, Hurwitz shortcut for a third order systemTutorialOld spec ENGR202Third6 min

ENGR202 (old spec) Control 3.5 Hurwitz Stability Criterion, Hurwitz shortcut example (slides 7-8)

Use the Hurwitz criterion, and its shortcut, to determine the stability of a system with characteristic equation 3s3+3s2+9s+6=03s^3 + 3s^2 + 9s + 6 = 0

Formulas you may need
  • Hurwitz criterion; shortcut: it is enough that either Δ1,Δ3,Δ5,⋯>0\Delta_1, \Delta_3, \Delta_5, \dots > 0 or Δ2,Δ4,⋯>0\Delta_2, \Delta_4, \dots > 0 (with all coefficients positive) (learn this)
  • Third order: stable if all coefficients are positive and a1a2>a0a3a_1a_2 > a_0a_3 (learn this)