Lecture 2 example, mass-spring-damperTutorialCurrent spec2:28 min

ENGR5001 Lecture 2 worked example 3, mass-spring-damper (slides 18-20)

A mass MM hangs from a fixed support by a spring of stiffness K′K' and a viscous damper of coefficient CC in parallel. An external force F(t)F(t) acts on the mass, and x(t)x(t) is the displacement of the mass from its static equilibrium position, measured in the direction of FF.

Formulas you may need
  • Newton's second law; spring force K′xK'x; viscous damper force CdxdtC\dfrac{dx}{dt} (learn this)
  • Generalised second order form d2xdt2+2ζωndxdt+ωn2x=Ku(t)\dfrac{d^2x}{dt^2} + 2\zeta\omega_n\dfrac{dx}{dt} + \omega_n^2 x = Ku(t), steady state gain K/ωn2K/\omega_n^2 (learn this)
  1. (a)
    State the additional assumption needed compared with the undamped harmonic oscillator, and derive the model.
  2. (b)
    Put the model into generalised second order form, giving KK, ωn\omega_n, ζ\zeta and the steady state gain in terms of MM, CC and K′K'.
  3. (c)
    How does the time response differ from that of the harmonic oscillator?