Dynamics Session 2 Example 1TutorialCurrent spec2:212 min

ENGR5004 Dynamics Session 2 worked example 1 (slides 13-15) official answers

A projectile is launched at 10 m/s from a point on a plane surface that slopes downwards at 30∘30^\circ to the horizontal. The launch velocity makes an angle α=80∘\alpha = 80^\circ with the downhill part of the slope surface (so it points up and towards the downhill side, see the figure). The projectile lands further down the slope. Assume negligible aerodynamic drag and take g=9.81g = 9.81 m/s2^2.

Find the time of flight tt and the range RR measured along the slope.

Projectile launched at 10 m/s from a slope inclined at 30 degrees below the horizontal; the launch velocity makes angle alpha with the downhill slope; R is the distance along the slope to the landing point.
Projectile launched at 10 m/s from a slope inclined at 30 degrees below the horizontal; the launch velocity makes angle alpha with the downhill slope; R is the distance along the slope to the landing point.
Formulas you may need
  • Constant acceleration: v=v0+actv = v_0 + a_c t, s=s0+v0t+12act2s = s_0 + v_0 t + \tfrac12 a_c t^2 (learn this)
  • Projectile (no drag): ax=0a_x = 0, ay=−ga_y = -g (learn this)