Dynamics Session 1 Example 1TutorialCurrent specThird6 min

ENGR5004 Dynamics Session 1 worked example 1 (slides 17-19) official answers

A rotating crank drives a slotted yoke so that point P on the horizontal rod moves in a straight line. Its position as a function of time is

s=0.4sin⁡(2πt) ms = 0.4\sin(2\pi t)\ \text{m}

with tt in seconds and ss measured to the right.

Scotch-yoke mechanism: a crank rotating about a fixed pin drives a slotted yoke; point P at the end of the horizontal rod moves along a straight line, with position s measured to the right.
Scotch-yoke mechanism: a crank rotating about a fixed pin drives a slotted yoke; point P at the end of the horizontal rod moves along a straight line, with position s measured to the right.
Formulas you may need
  • Rectilinear motion: v=dsdtv = \dfrac{ds}{dt}, a=dvdt=d2sdt2a = \dfrac{dv}{dt} = \dfrac{d^2s}{dt^2} (learn this)
  1. (a)
    Find the velocity and acceleration of P at t=0.375t = 0.375 s.
  2. (b)
    What is the maximum magnitude of the velocity of P?
  3. (c)
    When the magnitude of the velocity of P is a maximum, what is the acceleration of P?