Dynamics S2 slide 17: WE2 position from velocity (ENGR5004) - Revisica

Dynamics S2 slide 17: WE2 position from velocityFrom lectureCurrent spec2:26 marks8 min

ENGR5004 Dynamics Session 2, slide 17 (Self Study Examples, WE2)

The velocity of a particle is

$\mathbf v = 16t^2\,\mathbf i + 4t^3\,\mathbf j + (5t + 2)\,\mathbf k\ \ \text{m/s}$

When $t = 0$ , $x = y = z = 0$ .

Find the particle's coordinate position and the magnitude of its acceleration when $t = 2$ s.

Formulas you may need

$\mathbf r = \int \mathbf v\,dt$ component by component, with the initial position (learn this)
$\mathbf a = \dfrac{d\mathbf v}{dt}$ , $a = \sqrt{a_x^2 + a_y^2 + a_z^2}$ (learn this)

x

=

m

y

=

m

z

=

m

a

=

\mathrm{m/s^{2}}

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