Dynamics Session 1 Example 2TutorialCurrent spec2:210 min

ENGR5004 Dynamics Session 1 worked example 2 (slides 21-22) official answers

After landing, an airplane deploys its drag parachute and travels along a straight runway with an acceleration

a=−0.004 v2 m/s2a = -0.004\,v^2\ \text{m/s}^2

where vv is its speed in m/s.

Formulas you may need
  • a=dvdta = \dfrac{dv}{dt}, so for a=a(v)a = a(v): ∫v0vdva(v)=∫t0tdt\displaystyle\int_{v_0}^{v}\frac{dv}{a(v)} = \int_{t_0}^{t} dt (learn this)
  • a ds=v dva\,ds = v\,dv, so for a=a(v)a = a(v): ∫v0vv dva(v)=∫s0sds\displaystyle\int_{v_0}^{v}\frac{v\,dv}{a(v)} = \int_{s_0}^{s} ds (learn this)
  1. (a)
    Determine the time required for the velocity to decrease from 80 m/s to 10 m/s.
  2. (b)
    What distance does the plane cover during that time?