ENGR216 2025 Q B2Past paperOld spec ENGR2162:125 marks30 min

ENGR216 Summer 2025 Q B2[VALID] official answers

A particle (P) of mass (mm) slides in a tube with the relative velocity of vrelv_{rel}. The tube and the rod (perpendicular to the tube) rotate counterclockwise about point O with angular velocity ω\omega and angular acceleration α\alpha. At the instant shown in Figure B2, the horizontal and vertical distance between O and P is LL and hh, respectively. μk\mu_k and μs\mu_s are the kinetic and static friction coefficients between P and the tube.

Figure B2: rod of length L pinned at O carrying a perpendicular tube; particle P at height h above the rod, moving up the tube at v_rel.
Figure B2: rod of length L pinned at O carrying a perpendicular tube; particle P at height h above the rod, moving up the tube at v_rel.
Formulas you may need
  • Rotating-axes acceleration: aP=aO+(aP/O)rel+α×rP/O+2ω×(vP/O)rel+ω×(ω×rP/O)\mathbf{a}_P = \mathbf{a}_O + (\mathbf{a}_{P/O})_{rel} + \boldsymbol\alpha\times\mathbf{r}_{P/O} + 2\boldsymbol\omega\times(\mathbf{v}_{P/O})_{rel} + \boldsymbol\omega\times(\boldsymbol\omega\times\mathbf{r}_{P/O}) (given in the question)
  • Unit-vector cross products: k×i=j\mathbf{k}\times\mathbf{i} = \mathbf{j}, k×j=−i\mathbf{k}\times\mathbf{j} = -\mathbf{i} (learn this)
  • Newton's second law for a particle: ∑F=ma\sum\mathbf{F} = m\mathbf{a}, in components (learn this)
  • Kinetic friction F=μkNF = \mu_k N, opposing the relative sliding; static F≤μsNF \le \mu_s N only when there is no sliding (learn this)
  1. (a)
    Draw the free-body and kinetic diagrams of the particle P. State appropriate coordinate systems.
    [10]
  2. (b)
    Determine the acceleration of the particle P. Hint: use the following equation: aP=aO+(aP/O)rel+α×rP/O+2ω×(vP/O)rel+ω×(ω×rP/O).a_P = a_O + (a_{P/O})_{rel} + \alpha \times r_{P/O} + 2\omega \times (v_{P/O})_{rel} + \omega \times (\omega \times r_{P/O}).
    [10]
  3. (c)
    Determine the normal force and friction force of the particle P.
    [5]2:2