Dynamics S3 slides 5-6: Roller coaster and shuttlecock at the bottom of the pathFrom lectureCurrent spec2:25 marks5 min

ENGR5004 Dynamics Session 3, slides 5-6 (Applications of a particle in curvilinear motion (2) and (3))

A roller coaster travels down a hill whose path can be approximated by a function y=f(x)y = f(x). It starts from rest and increases its speed at a constant rate. Similarly (slide 6), a shuttlecock launched by a robot's firing system follows a path approximated by y=f(x)y = f(x).

Formulas you may need
  • ρ=[1+(dy/dx)2]3/2∣d2y/dx2∣\rho = \dfrac{[1 + (dy/dx)^2]^{3/2}}{|d^2y/dx^2|} (learn this)
  • at=v˙a_t = \dot v, an=v2ρa_n = \dfrac{v^2}{\rho}, a=at2+an2a = \sqrt{a_t^2 + a_n^2} (learn this)
  • Constant ata_t: v=v0+attv = v_0 + a_t t, v2=v02+2at(s−s0)v^2 = v_0^2 + 2a_t(s - s_0) (learn this)
  1. (a)
    How can we determine the velocity and acceleration at the bottom of the path?
    [4]
  2. (b)
    Why would we want to know these values?
    [1]