Old spec Statics Session 11 Example 2TutorialOld spec ENGR2162:28 min

ENGR216 (old spec) Statics session 11 worked example 2 (slides 9-10) official answers

A cantilever AB of length 2L2L and flexural rigidity EIEI, fixed at A, carries a downward concentrated load PP at its midpoint C (AC=CB=LAC = CB = L).

You may use the result for a cantilever of length LL with an end load PP: θ(x)=1EI[−PLx+Px22]\theta(x) = \dfrac{1}{EI}\left[-PLx + \dfrac{Px^2}{2}\right], y(x)=1EI[−PLx22+Px36]y(x) = \dfrac{1}{EI}\left[-\dfrac{PLx^2}{2} + \dfrac{Px^3}{6}\right].

Cantilever AB of length 2L fixed at A; downward load P at the midpoint C, AC = CB = L.
Cantilever AB of length 2L fixed at A; downward load P at the midpoint C, AC = CB = L.
Formulas you may need
  • Elastic curve: d2ydx2=M(x)EI\dfrac{d^2y}{dx^2} = \dfrac{M(x)}{EI}, slope θ=dydx\theta = \dfrac{dy}{dx} (learn this; on the 2025 sheet but not the 2026 one)
  • Unloaded segment: M=0M = 0, so it stays straight (rigid rotation), small angles yB≈yC+LθCy_B \approx y_C + L\theta_C (learn this)
  1. (a)
    Sketch the deformed shape of the beam.
  2. (b)
    Calculate the maximum deflection of the beam.