ENGR216 2022 Statics Q A1Past paperOld spec ENGR2162:125 marks30 min

ENGR216 Summer 2022 Statics Q A1[VALID] official answers

Consider the cantilevered structure of Figure A1, loaded by a parabolic distributed normal load w(x)w(x), given by

w(x)=w0[−(xL)2+2(xL)](1)w(x) = w_0\left[-\left(\frac{x}{L}\right)^2 + 2\left(\frac{x}{L}\right)\right] \qquad (1)

where xx is the coordinate along the mean line of the horizontal member BC (origin at B), which has length LL.

Figure A1: column AB fixed at A, horizontal member BC of length L with parabolic load reaching w0 at C.
Figure A1: column AB fixed at A, horizontal member BC of length L with parabolic load reaching w0 at C.
Formulas you may need
  • Equilibrium of a rigid body: ∑Fx=0\sum F_x = 0, ∑Fy=0\sum F_y = 0, ∑MA=0\sum M_A = 0 (learn this)
  • Resultant of a distributed load P=∫w dxP = \int w\,dx and its position xP=∫x w dx∫w dxx_P = \dfrac{\int x\,w\,dx}{\int w\,dx} (on the formula sheet)
  • Load, shear and moment: dVdx=−w(x)\dfrac{dV}{dx} = -w(x), dMdx=V(x)\dfrac{dM}{dx} = V(x), positive shear and bending as pictured (on the formula sheet)
  • Elastic curve EI d2ydx2=M(x)EI\,\dfrac{d^2y}{dx^2} = M(x), so θC−θB=1EI∫BCM dx\theta_C - \theta_B = \dfrac{1}{EI}\displaystyle\int_B^C M\,dx (learn this; on the 2025 sheet but not the 2026 one)
  • Combined axial force and bending: σx=NA−MyI\sigma_x = \dfrac{N}{A} - \dfrac{M y}{I}, ∣σ∣max=∣N∣A+∣M∣cI|\sigma|_{max} = \dfrac{|N|}{A} + \dfrac{|M| c}{I} (on the formula sheet, as eccentric axial loading)
  • Solid circle: A=πr2A = \pi r^2, I=πr44I = \dfrac{\pi r^4}{4} (on the formula sheet)
  1. (a)
    Draw the free-body-diagram of the entire structure, indicating all nonzero reactions.
    [7]2:2
  2. (b)
    Demonstrate that the bending moment exerted by the fixed support at A has magnitude MA=512w0L2(2)M_A = \frac{5}{12} w_0 L^2 \qquad (2) and state if this moment is clockwise or counter-clockwise.
    [6]2:2
  3. (c)
    Knowing that the bending moment M(x)M(x) along the horizontal member BC is M(x)=w0L2[112(xL)4−13(xL)3+23(xL)−512](3)M(x) = w_0 L^2\left[\frac{1}{12}\left(\frac{x}{L}\right)^4 - \frac{1}{3}\left(\frac{x}{L}\right)^3 + \frac{2}{3}\left(\frac{x}{L}\right) - \frac{5}{12}\right] \qquad (3) determine the rotation of section C relative to section B as a function of w0w_0, LL, and the flexural rigidity EIEI.
    [6]
  4. (d)
    The cross section of members AB and BC are circular with radius of 50 mm, L=1L = 1 m and the allowable normal stress of the material is 150 MPa. Briefly explain which cross section(s) of the given structure have maximum magnitude of the normal stress, and calculate the maximum value of w0w_0 in kN/m such that the normal stress in all cross sections of AB and BC never exceeds the allowable normal stress.
    [6]